-41.19*x^2+6.75*x-0.105=0

Solution for -41.19*x^2+6.75*x-0.105=0 equation:

-41.19x^2+6.75x-0.105=0

a = -41.19; b = 6.75; c = -0.105;
Δ = b2-4ac
Δ = 6.752-4·(-41.19)·(-0.105)
Δ = 28.2627
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.75)-\sqrt{28.2627}}{2*-41.19}=\frac{-6.75-\sqrt{28.2627}}{-82.38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.75)+\sqrt{28.2627}}{2*-41.19}=\frac{-6.75+\sqrt{28.2627}}{-82.38}
$